Question

find the perimeter of the rectangle whose length is 20m and diagonal is 60cm​

Answer 1

$\huge\mathbb{SOLUTION:-}$

$\bold{Given:-}\begin{cases}\sf{Length\:of\: rectangle=20m}\\ \sf{Diagonal\:of\: rectangle:-60cm}\end{cases}$

$\huge\sf{\star{To\:Find:-}}$

• The perimeter of rectangle

$\sf\underline{Step\:By\:step\: Explanation:-}$

• Find the breadth or side of rectangle by Pythagoras theorm..

$\boxed{\star{\sf{Diagonal {}^{2}=base{}^{2}+perpendicular {}^{2}}}}$

$\sf\implies 60{}^{2}=20{}^{2}+breadth{}^{2}\\ \\ \sf\implies 3600=400+breadth{}^{2}\\ \\ \sf\implies 3600-400=breadth{}^{2}\\ \\ \sf\implies 3200=breadth{}^{2}\\ \\ \sf\implies breadth=\sqrt{3200}\\ \\ \sf\implies breadth= 56.57cm$

• The breadth of rectangle is 56.69cm
• Now the perimeter of rectangle

$\boxed{\sf{Perimeter\:if\: rectangle=2(l+b)}}$

$\sf\implies perimeter=2(20+56.57)\\ \\ \sf\implies Perimeter=2\times 76.57cm\\ \\ \sf\implies Perimeter\:of\: rectangule=153.14cm$

$\boxed{\sf{\red{Perimeter\:of\: rectangle=153.14cm}}}$

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Answer 2

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