find the perimeter of the rectangle whose length is 24 cm and the diagonal is 26 CM
IMAGINE THE RECTANGLE AS TRIANGLE
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0
Answer:
624 square is right answer
Answered by
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Answer:
68cm
Step-by-step explanation:
length=24
diagonal=26
using Pythagoras theorem
triangle BDC
DB^2= BC^2+DC^2
26^2=BC^2+24^2
676-576=BC^2
BC^2=100
BC=√100
BC=10
BC= Breadth
perimeter of rectangle=2(l+b)
=2(24+10)
=2(34)
=68
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