Question

find the perimeter of the rectangle whose length is 32 cm and a diognal is 40 cm​

Answer 1

Answer:

Step-by-step explanation:

P=112cm is the answer

Answer 2

Answer:

112 cm

Step-by-step explanation:

perimeter = 2(l + b)

diagnol = 40cm

length = 32cm

diagnol = √(l^2 +b^2)

thus...

perimeter = 2l + 2√(d^2- l^2)

perimeter = 2×32 + 2√ ( 40^2 - 32^2)

perimeter = 112cm