Question

find the perimeter of the rectangle whose length is 40 cm and diagonal is 41. (pythagorus theorum)

Answer 1

Answer:

9 cm

Step-by-step explanation:

In a rectangle:

One length, one breadth and one diagonal which are adjacent form a right angled triangle:

In which,

Perpendicular = breadth

{Let breadth be x}

Base = Length = 40cm

Hypotenuse = Diagonal = 41 cm

Now it is right angled triangle,

So, by Pythagoras theorem:

(41)² = (40)² + (x)²

= 1681 = 1600 + x²

= x² = 1681 - 1600

= x² = 81

= x² = 9²

= x = 9

So, Breadth = x = 9 cm

Hope, you got it :-))

Please, mark it as brainiest!!

Answer 2

Answer:

b²=41²-40²

b²=1681-1600

b²=81

b²=root of 81

b=9