Question

Find the perimeter of the rectangle whose length is 40 cm and a diagonal is 41

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Answer 1

Step-by-step explanation:

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Answer 2

Question :

☯ Find the perimeter of the rectangle whose length is 40 cm and a diagonal is 41 cm.

Given :

→ Length = 40 cm

→ Diagonal = 41 cm

Answer :

Perimeter of Rectangle = 98 cm

Explanation:

Perimeter of Rectangle = 2(Length + Breadth)

In question :

Length is given but breadth is not given. So we need to find Breadth to find perimeter of Rectangle

Remember  :-

When Length and diagonal are given for a rectangle or square, it forms a triangle

Here the diagonal is Hypotenuse of Triangle

We can find The Hypotenuse of a Triangle using Pythagoras Theorem

• Pythagoras Theorem state that: Square of Hypotenuse side equalto sum of square of 1st side and square of 2nd side

If AC is Hypotenuse ,then :

AC² = AB² + BC²

We have to find the BC² according to question

(41)² = (40)² + BC²

1681 = 1600 +  BC²

BC² = 1681 - 1600

       = 81

√(BC)² = √81

BC = 9 cm

Hence Breadth is 9 cm

Perimeter of Rectangle = 2(Length + Breadth)

Perimeter of Rectangle = 2(40 cm + 9cm)

Perimeter of Rectangle = 2(49 cm)

Perimeter of Rectangle = 98 cm

Refer to Attachment for clear understanding of figure

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