Question

Find the perimeter of the rectangle whose length is 40 cm, and a diagonal is 41 cm​

Answer 1

Answer:

By Pythagoras theorem,

(Diagonal)^2=(Length)^2+(Width)^2

Now as given in the question,

Diagonal = 41 cm.

Length = 40 cm.

So, Putting these value we get,

(41)^2=(40)^2+(Width)^2

(Width)^2=(41)^2-(40)^2

(Width)^2=1681-1600

(Width)^2=81

Width=9cm

Hence the width of the rectangle is 9 cm.

So

The perimeter of the rectangle = 2 ( Length + Width )

= 2 ( 40 cm + 9 cm )

= 2 x 49 cm

= 98 cm

Hence the perimeter of the rectangle is 98cm

hope this would help u

Answer 2

Step-by-step explanation:

the diagonal of rectangle is 41cm

the lenght of the rectangle is 40cm

√41^2-40^2=√81= 9= height

the perimeter of the rectangle = 2(h+l)

2(9+40)

2(49)

98cm