Question

find the perimeter of the rectangle whose length is 40cm and adiagonal is 41cm solve this question

Answer 1

HOPE IT HELPS YOU

USING PYTHAGORAS THEOREM :

( that part i am explaining it step by step here )

AC^2 = AD^2 - DC^2

= ( 41 )^2 - ( 40 )^2

= 1681 - 1600

= 81

AC = 9 cm

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Answer 2

let the rectangle be ABCD

and bredth = BC = X

Given that , length = AB = 40cm

and a diagonal = 41cm

therefore by pythagoras theorm ,

(length)²+(bredth)²=(diagonal)²

therefore, 40²+X² = 41²

therefore, X = 9

Perimeter of rectangle = 2(l+b)

                                     =2(40+9)

                                     =2 x 49

                                     =98cm