Math, asked by Russy8349, 1 year ago

Find the perimeter of the rectangular field whose length is 4 times its width and which has area equal to 20730 sq.M

Answers

Answered by hsbbzvsvsmss
0
let the width be of x m
therefor its lenght =4xm
now lb=20730
=x(4x)=20730
4x^2=20730
x=√20730/√4
=√20730/2m
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