Question

Find the perimeter of the rectangular whose length is 40cm and a diagonal is41cm​

Answer 1

Answer:

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Step-by-step explanation:

we can see in the rectangle,

By Pythagoras theorem,

(Diagonal)^2=(Length)^2+(Width)^2

Now as given in the question,

Diagonal = 41 cm.

Length = 40 cm.

So, Putting these value we get,

(41)^2=(40)^2+(Width)^2

(Width)^2=(41)^2-(40)^2

(Width)^2=1681-1600

(Width)^2=81

Width=9cm

Hence the width of the rectangle is 9 cm.

So

The perimeter of the rectangle = 2 ( Length + Width )

= 2 ( 40 cm + 9 cm )

= 2 x 49 cm

= 98 cm

Hence the perimeter of the rectangle is 98 cm.