Question

find the perimeter of the sector of the circle of radius 6 cm if angle of the sector is 60°.​

Answer 1

radius (r) = 6 cm

central angle (x) = 60°

we know that,

perimeter(sector) = length(arc) + 2r

perimeter(sector)

$= ( \frac{x}{ {180}^{o}} \times \pi \: r \:) + 2r \\ = (\frac{60}{180} \times \frac{22}{7} \times 6 )+ 2(6) \\ =( \frac{1}{3} \times \frac{22}{7} \times 6) + 12 \\ = \frac{44}{7} + 12 \\ = \frac{44 + 84}{7} \\ = \frac{128}{7}$

Hence, perimeter of the sector would be (128/7) cm.

Answer 2

Answer:

123)7

is the answer

perimeter will be this