find the perimeter of the square if its diagonal is 10 root 2 cm
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by patha goras theorem if side of square is a
10√2*10√2=a*a+a*a
200=2a*a
100=a*a
a=10cm
perimeter=4*a
=4*10=40cm
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diagonal of square = √2×side of square
10√2 =√2 × side of square
side of square = 10 cm
perimeter of square =4*side
=40 cm
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