Question

find the perimeter of the square whose are 400 sq.m​

Answer 1

Step-by-step explanation:

Therefore area of a square = (side)²

and area in our case = 400m²

Therefore,

400=(side)²

Root of 400 = 20m

Therefore perimeter = 4×side

Therefore perimeter = 4×20=80m

This is your required answer..

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pls mark brainliest

Answer 2

$\huge{ \underline{ \overline{ \mid{ \mathfrak{ \purple{ \: \: SOLUTION \: \: } \mid}}}}}$

$\mathfrak{ \: Suppose,} \\ \\ \: \: \: \: \: \text{The side of the square = a} \\ \\ \underline{ \mathfrak{ \: \: Given, \: \: }} \\ \\ \text{Area of the square = 400 sq. m} \\ \\ \\ \underline{ \mathfrak{To \: \: find : \mapsto}} \\ \\ \text{ Perimeter of the square = ? }$

$\underline{ \mathfrak{ \: \: We \: \: know \: \: that, \: \: }} \\ \\ \boxed{\mathtt{Area \: \: of \: \: a \: \: square =(side) {}^{2} } }$

$\underline{ \bold{ \: \: A.T.Q., \: \: }} \\ \\ \: \: \: \: \: \: \tt{400 = a {}^{2} } \\ \\ \tt{\Longrightarrow \: a {}^{2} = 400 } \\ \\ \tt{\Longrightarrow \: a = \sqrt{400} } \\ \\ \tt{\Longrightarrow \: a = \pm \: 20}$

$\text{As the side of a square can't be negative,} \\ \\ \therefore \: \: \text{Side of the square, a = 20 m}$

$\mathfrak{ \: Now, \: } \\ \\ \underline{ \mathfrak{ \: \: We \: \: know \: \: that, \: \: }} \\ \\ \boxed{ \tt{Perimeter \: \: of \: \: a \: \: square = 4 \times side \: }}$

$\tt{ \therefore \: \: Perimeter \: \: of \: \: the \: \: square = 4a} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \tt{ =( 4 \times 20) \: m} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \tt{ = 80 \: \: m}$

$\therefore \: \: \text{ Perimeter of the square = 80 m }$