Question

find the perimeter of the triangle formed by the points (0,0),(1,0),(0,1) ​

Answer 1

Answer:

According to this question:

Let the points be A(0,0), B(1,0)& C(0,1)

⚫The distance between two points always taken as positive.

Using the formula of distance between two points:

=) AB= √(0-1)² + (0-0)²

=) AB = √1 + 0

=) AB =√1

=) AB= 1

BC= √(1-0)² + (0-1)²

=) BC= √1 + 1

=) BC = √2

CA = √(0-0)² +(1-0)²

=) CA= √0 + 1

=) CA = √1

=) CA = 1

Therefore,

We know that perimeter of triangle is;

Side + side + side

=) AB + BC + AC

=) 1 + √2 + 1

=) 2+ √2

Hence,

The perimeter of ∆ is 2+√2.

Explanation:

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