Question

find the perimeter of the triangle having vertices (4, 0) , (2, 2), (0, 0).​

Answer 1

Step-by-step explanation:

Correct option is

C

12

Let ABC be a triangle having A(0,4);B(0,0);C(3,0)

Using distance formula, we get

AB=

(0−0)

2

+(0−4)

2

=

16

=4

BC=

(3−0)

2

+(0−0)

2

=

9

=3

CA=

(0−3)

2

+(4−0)

2

=

25

=5

Perimeter of △ABC=AB+BC+CA=4+3+5=12