Question

find the perimeter of the triangle whose vertices are (5, 2) (4, 7) (7, -4)​

Answer 1

Answer:

Step-by-step explanation:

Let A (3,10); B(5,2);C(14,12)

area of triangle ABC = 1/2 [ x 1(y 2-y 3)+x 2(y 3-y 1)+x 3(y 1-y 2)

                                 = 1/2 [ 3(2-12)+5(12-10)+14(10-2)]

                                 = 1/2 [3 (-10)+5(2)+14(8)]

                                 = 1/2 [-30+10+112]

                                 = 1/2 [92]

                                 = 46 sq. units

HOPE IT HELPS YOU!