Find the perimeter of triangle pbc of PQ is 7cm
Answers
Answer:
In the given triangle,
PQ=PR (Tangents from the external point P)
XB=BQ (Tangents from the external point B)
XC=CR (Tangents from the external point C)
Perimeter of △PCB is PC+CB+PB but CB=CX+XB,
Therefore, perimeter of △PCB is PC+CX+XB+PB but CX=CR and XB=BQ
Therefore, perimeter of △PCB is PC+CR+PB+BQ but PC+CR=PR and PB+BQ=PQ
Therefore, perimeter of △PCB is PR+PQ but PQ=PR=7 cm [As length of the tangents drawn from an external point are equal]
Hence, perimeter of △PCB is 7+7=14 cm.
Step-by-step explanation:
In the given circle,
PQ=PR (Tangents from the external point P)
XB=BQ (Tangents from the external point B)
XC=CR (Tangents from the external point C)
Perimeter of △PCB is PC+CB+PB but CB=CX+XB,
Therefore, perimeter of △PCB is PC+CX+XB+PB but CX=CR and XB=BQ
Therefore, perimeter of △PCB is PC+CR+PB+BQ but PC+CR=PR and PB+BQ=PQ
Therefore, perimeter of △PCB is PR+PQ but PQ=PR=7 cm [As length of the tangents drawn from an external point are equal]
Hence, perimeter of △PCB is 7+7=14 cm.