Question

find the perimeter of triangle where sides are 3a+2b,a-b,2b-49​

Answer 1

Answer:

refer to the image for solution

hope it will help you

Answer 2

Question:

Find the perimeter of triangle where sides are 3a+2b,a-b,2b-49​

Given:

The three sides of triangle 3a+2b,a-b,2b-49​ respectively

To Find:

Perimeter

Solution:

Perimeter of a triangle = $s_{1} +s_{2} +s_{3}$

$3a+2b+a-b+2b-49\\\\\\(3a+a)+(2b+2b-b)-49\\\\\\4a+3b-49$

= 4a + 3b - 49

Answer:

Therefore the perimeter of the triangle = 4a + 3b - 49

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