Find the perimeter of triangle with vertices (0,4) , (0,0) & (3,0)
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let the points be of vertices A,B and C
A = (0,4) y =4
B = (0,0) origin
C = (3,0) x = 3
Thus B is the right angle for triangle ABC
AB = 4
BC = 3
AC = 5
A = (0,4) y =4
B = (0,0) origin
C = (3,0) x = 3
Thus B is the right angle for triangle ABC
AB = 4
BC = 3
AC = 5
rs873418:
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