Find the perimeter with vertices (0,5) , (6,0) ,(2,0)
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Triangle ABC with the vertices
A = (0,0), B = (2,4), C = (5,1)
The sides will be:
AB, BC, and AC
Calculate the total length of the sides
AB =(2-0,4-0) = (2,4) Yielding into a length of (22 +42)1/2 =4.47
BC =(5-2, 1-4) =(3,-3) length (32 + -32)1/2 =4.24
AC = (5-0,1-0) =(5,1) length (52 +12)1/2 =5.1
Perimeter is 4.47 + 4.24 + 5.1 = 13.81
A = (0,0), B = (2,4), C = (5,1)
The sides will be:
AB, BC, and AC
Calculate the total length of the sides
AB =(2-0,4-0) = (2,4) Yielding into a length of (22 +42)1/2 =4.47
BC =(5-2, 1-4) =(3,-3) length (32 + -32)1/2 =4.24
AC = (5-0,1-0) =(5,1) length (52 +12)1/2 =5.1
Perimeter is 4.47 + 4.24 + 5.1 = 13.81
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