Find the period for the function: cos⁴ x
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we know, cos²x = (1 + cos2x)/2
so, cos⁴x = (cos²x)²
= {(1 + cos2x)/2}²
= (1 + cos2x)²/4
= (1 + cos²2x + 2cos2x)/4
= 1/4 + cos²2x/4 + cos2x/2
= 1/4 + (1 + cos4x)/8 + cos2x/2
so, period of cos⁴x = period of 1/4 + (1 + cos4x)/8 + cos2x/2
we know, period of cosx = 2π
period of cos2x = 2π/2 = π
period of cos4x = 2π/4 = π/2
so, period of 1/4 + (1 + cos4x)/8 + cos2x/2 = LCM { period of cos2x , period of cos4x}
= LCM { π , π/2}
= π
hence, period of cos⁴x = π
so, cos⁴x = (cos²x)²
= {(1 + cos2x)/2}²
= (1 + cos2x)²/4
= (1 + cos²2x + 2cos2x)/4
= 1/4 + cos²2x/4 + cos2x/2
= 1/4 + (1 + cos4x)/8 + cos2x/2
so, period of cos⁴x = period of 1/4 + (1 + cos4x)/8 + cos2x/2
we know, period of cosx = 2π
period of cos2x = 2π/2 = π
period of cos4x = 2π/4 = π/2
so, period of 1/4 + (1 + cos4x)/8 + cos2x/2 = LCM { period of cos2x , period of cos4x}
= LCM { π , π/2}
= π
hence, period of cos⁴x = π
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