find the period of cos⁴x ?
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Answer:
pi
Step-by-step explanation:
Answered by
0
Answer:
Step-by-step explanation:
we know, cos²x = (1 + cos2x)/2
so, cos⁴x = (cos²x)²
= {(1 + cos2x)/2}²
= (1 + cos2x)²/4
= (1 + cos²2x + 2cos2x)/4
= 1/4 + cos²2x/4 + cos2x/2
= 1/4 + (1 + cos4x)/8 + cos2x/2
so, period of cos⁴x = period of 1/4 + (1 + cos4x)/8 + cos2x/2
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