Find the perpendicular components of a force of 50N making an angle of 30° with x axis.
Answers
Answer:
see the attachment please
Explanation:
Hope the answer will help you
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The perpendicular components of a force of 50N making an angle of 30° with an x-axis is 25 N.
Given: A force of 50 N making an angle of 30° with the x-axis.
To Find: The perpendicular components of a force.
Solution:
- We know that the vertical component of a vector which is making an angle with the x-axis can be determined by the formula,
Perpendicular component = A sin Ф .....(1)
where A = a vector, Ф = angle made by vector A with the x-axis
Coming to the numerical, we are given that force (F) = 50 N, Ф = 30°,
So, putting the respective values in (1), we get;
Perpendicular component = A sin Ф
⇒ Perpendicular component = 50 sin 30°
⇒ Perpendicular component = ( 50 × 1/2 ) N
= 25 N
Hence, the perpendicular components of a force of 50N making an angle of 30° with an x-axis is 25 N.
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