Question

find the perpendicular distance of the point (2,-3) from the line 2x-3y-25=0​

Answer 1

Answer:

ANSWER

Equation of

′

AB

′

is given by

y−5=

4

3

(x−2)

⇒4y−20=3x−6

⇒3x−4y+14=0 ..(i)

3x+y+4=0 ..(ii)

(i) - (ii)

−5y+10=0

∴y=2

∴3x−8+14=0

⇒3x=−6

∴x=−2

∴B(−2,2)

Hence, AB=

(2+2)

2

+(5−2)

2

∴AB=

3

2

+4

2

∴AB=

9+16

∴AB=5

solution