Question

find the pH of 0.002 N acetic acid solution,it is 2.3% ionized at given dilution.

Answer 1

Hi,

This is how we go through the calculation of pH.

Concentration 0.002 N

Degree of ionization 2.3%

Then we can go a head by calculating the equilibrium concentration of acetic acid.

Equilibrium concentration = C∝

Where C is the concentration and ∝ is the degree of ionization.

                                            = 0.002 x 2.3/100

                                            = 4.6 x 10^-5 M

Then pH= -log concentration

         pH= -log 4.6 x 10^-5

              = 4.3.

Answer 2

Here is your answer,
Hope this answer helps you,
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