Question

find the ph pf koh solutions whose concentration is 0.001M​

Answer 1

Answer:

PH= -log(H+)

KOH - Strong base

KOH ----> K+ + OH-

[OH-] = 10^(-3)

P(OH)= -log{10^(-3)} = 3

P(H) +P(OH) =P(Kw) =14

PH +3 =14

PH=11