Question

find the point an the x axis which is equidistamt for the point (2,-5) and (-2,9)​

Answer 1

Answer:(-7,0)

Step-by-step explanation:

Let the point A be on the X--Axis i.e.point A(x,0).

Let the points be B(2,-5) and C(-2,9).

Now it is given that point A is equidistance from point(2,-5) and point(-2,9).

So from distance formula,

AB^2=(x-2)^2+(0-5)^2

And,

AC^2=(x+2)^2+(0-9)^2.

But AB =AC

=>(x-2)^2+(0-5)^2=(x+2)^2+(0-9)^2

Some steps are omitted...after solving the equation you will get,

=>x=-7

Hence ,the coordinate point is A(-7,0)