Math, asked by sofiya02, 5 hours ago

FIND the point of inflexion of the function
y=1/3 x³ - 5/2x² + 6x - 12




Answers

Answered by amardeepsharma1973
0

Answer:

(1,19);(2,33)

Step-by-step explanation:

y=x4−6x3+12x2+5x+7

y(x)=4x3−18x2+24x+5

y(x)=12x2−36x+24

y(x)=0

12x2−36x+24=0

x2−3x+2=0

x2−2x−x+2=0

x(x−2)−1(x−2)=0

(x−1)−1(x−2)=0

(x−1)(x−2)=0

x=1,2

Inflection point of a function is where the function changes from concave up to concave down or vice-versa

x<1,f(x)>0

1<x<2,f(x)<0

x>2,f(x)>0

∵f(x) changes sign

∴ At x=1,2y=f(x) has inflection point 

At x=1,y=f(1)=19

At x=2,y=f(2)=33

Point of inflection (1,19);(2,33)

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