find the point of intersection
of the curves r²=4cos theeta and r= 1-cos theeta
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Answer:
Answer
A. S. Adikesavan
Nov 23, 2016
(
2
(
√
2
−
1
)
,
cos
−
1
(
3
−
√
2
)
)
=
(
0.8284
,
80.12
o
)
Explanation:
r > 0.
Eliminate r.
r
2
=
(
1
−
cos
θ
)
2
=
4
cos
θ
Solving,
cos
θ
=
3
−
2
√
2
→
θ
=
a
r
c
cos
(
3
−
2
√
2
)
→
r
=
2
(
(
√
2
−
1
)
.
So, the common point is
(
2
(
√
2
−
1
)
,
cos
−
1
(
3
−
√
2
)
)
=
(
0.8284
,
80.12
o
)
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