find the point of intersection of the straight lines 2x+3y=6,y=0
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Answer:
x = 10/2 - 3y/2 , or
x = 5 -3y/2…(1)
3x+2y = 5, or
3x = 5–2y, or
x = (5/3)-2y/3 …(2)
Equate (1) and (2)
5 -3y/2 = (5/3)-2y/3 or
30–9y =10 -4y, or
5y = 20, or y = 4.
From (2), x = (5/3)-(8/3) = (-3/3) = -1
Step-by-step explanation:
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