x2-6x+a=0 have equal roots,then find the value of a
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x²-6x+a =0 have equal roots
If roots are equal then discriminant=b²-4ac
therefore B²-4AC
A=1 B= -6 C=a
36-4a=0
36=4a
a=9
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Solution:
x^2 - 6x + a = 0
If x = 3 (equal roots)
x^2 - 6x + a = 0
3^2 - 6(3) + a = 0
9 - 18 + a = 0
-9 + a = 0
a = 9
Therefore, x^2 - 6x + 9 = 0
(x - 3) (x - 3) = 0
x = 3
Hope this will be helpful.
x^2 - 6x + a = 0
If x = 3 (equal roots)
x^2 - 6x + a = 0
3^2 - 6(3) + a = 0
9 - 18 + a = 0
-9 + a = 0
a = 9
Therefore, x^2 - 6x + 9 = 0
(x - 3) (x - 3) = 0
x = 3
Hope this will be helpful.
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