Find the point on the line 2x+5y+4=0 whose ordinate is 5.
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Answer:
( - 14.5 , 5 )
Step-by-step explanation:
Let the required point be ( a , 5 )
As ( 5 , a ) lies on 2x + 5y + 4 = 0 :
⇒ 2( a ) + 5( 5 ) + 4 = 0
⇒ 2a + 25 + 4 = 0
⇒ 2a + 29 = 0
⇒ 2a = - 29
⇒ a = - 29 / 2
Hence the required point is (- 14.5 , 5 )
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