find the point on the the x-axis which it is equidistant form(2,6) (-2,9)
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Answer:
We have to find a point on x-axis. Therefore, its y-coordinate will be 0.
Let the point on x-axis be (x,0)image
(x - 2)2 + 25 = (x - 2)2 + 81
x2 + 4 - 4x + 25 = x2 + 4 + 4x + 81
8x = 25 -81
8x = -56
x = -7
Therefore, the point is ( - 7, 0).
Answered by
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Answer:
2 and -2 is the correct answer..
Step-by-step explanation:
I hpe it will help you..
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