Question

Given P = (x²y + xy + 5x+7), Q = (3x² + x) and R=(2x2y-3xy + 5). Then find: Px (R-Q) ​

Answer 1

Answer:

Given, p(x)=2x

2

−5x+7 and q(x)=x−1

q(x) ⇒x−1=0 ⇒x=1

The remainder when p(x) is divided by q(x) is p(1) (By Remainder Theorem)

Thus,

p(1)=2(1)

2

−5(1)+7

p(1)=2−5+7

p(1)=4