Question

find the point on the x axis which is equal distance from (5, 4) and (-2, 3)

Answer 1

x,0 is equidistant from (5,4) , (-2,3)

(x-5)^2 + (0-4)^2 = (x-(-2)^2 + (0-3)^2
X^2 + 25 - 10x + 16 = x^2 +4 + 4x + 9
41-13= 4x + 10x (hence x^2 got cancelled )
28=14x
X= 2