Question

find the point on the x-axis which is equidistance from [ 2,-5] and [-2,9]​

Answer 1

Step-by-step explanation:

(2,-5)=x1,y1

(-2,9)=x2,y2

if x-axis then (x,0)

$p(x.y) = x1 + x2\div 2.y1+ y2 \div 2$

p(x,0)=2+(-2)/2, -5+9/2

x=2-2/2

x=0

point(0,0)

Answer 2

Answer:

answer attached in photo