Question

Find the point on the x- axis which is equidistant from ( 2 , -5 ) and (-2 , 9 ) .​

Answer 1

Answer:

2nd quadrant nd 4th quadrant

Answer 2

Step-by-step explanation:

let a=(2, -5) and b=(-2, 9) and c be the point btw a and b which is equidistant and it's coordinates be (x,y)

so,

ratio = 1:1

so x coordinate = 1/2(2+(-2)=1/2(0)=0

y coordinate = 1/2(-5+9) = 1/2(4) = 2

so coordinates are (0,2)

point on the x-axis is 0