Question

find the point on the X-axis which is equidistant from A(-3,4) and B(1,-4)​

Answer 1

Step-by-step explanation:

Let the point in X-axis be (x, 0)

then by distance formula we get,

√(x+3)^2+(4-0)^2=√(x-1)^2+(0+4)^2

On squaring both sides we get,

(x+3)^2+(4-0)^2=(x-1)^2+(0+4)^2

=x^2+9+6x+16=x^2+1-2x+16

=9+6x=1-2x

=8x=-8

=x=-1

Hence, the point on the X-axis which is equidistant from A(-3,4) and B(1,-4) is (-1, 0)

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