Question

find the point on the x-axis which is the equidistant from (2,-5) and (-2,9)

Answer 1

(x,0) is equidistant from(2,-5),(-2,9),so,

(x-2)^2 + (0-(-5)^2 =(x-(-2)^2 +( 0-9)^2
x^2+4-4x+25=x^2+4+4x + 81
-4x+25=4x+81
-4x-4x=81-25
-8x=56
x=-7

Answer 2

HOPE IT HELPS YOU...