Question

find the point on the y-axis that is equidistant from 5,-2 and -3,2

Answer 1

Answer:

formula =√{(x2-x1)square + (y2-y1)square}

according to question

when the point is on y axis then x will be zero

x=0

y=0

now there are two points and distance between 0,y and 5,-2 = first

0,y and -3,2 = second

using distance formula

I am doing here sort

[ 25+4+(y)square+4y ] is of first distance and second = 9+4+(y)square-4y

putting both in =

25+4+(y)square+4y = 9+4+(y)square-4y

29+4y=13-4y

29-13=-4y-4y

16=-8y

y=16/-8= -2

Ans= x =0 and y = -2

(one problem you may face (-2-y)square =2+y whole square)

Answer 2

Answer:

Step-by-step explanation: