Find the point on the y-axis, which is equidistant from the points A (-3, 2) and B ( 5, -2).
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Answer :-
P = (0, -2)
Given :-
The point on y- axis is equidistant from the point A (-3 , 2) and point B (5, -2)
To find :-
The point
Solution :-
Lets say that the point P on y-axis is equidistant from point A(-3,2) and B(5, -2)
So, as it is on the y-axis Since , x -axis is absent So, lets consider
P = ( 0, y )
A =( -3,2)
B = (5, -2)
As they are equidistant So,
PA = PB
- PA = Distance between P and A
- PB = Distance between P and B
By using distance formula
So,
PA = PB
Squaring on both sides
Transposing R.H.S terms to L.H.S
As we know that ,
(a+b)² = a²+2ab +b²
(a-b)² = a²-2ab+b²
So, y is -2 The required point P (0, y) = (0, -2)
So, the required point is (0, -2)
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