Question

Find the point on x axis which is equaidistant from A(-1, 2) B (5.4)​

Answer 1

Answer:

Step-by-step explanation:

given :

Find the point on x axis which is equaidistant from A(-1, 2) B (5.4)

to find :

equaidistant from A(-1, 2) B (5.4)

solution :

• AC² = BC²

• (x - 5)² + (0-4)² = (x + 2)² + (0 - 3)² x² - 10x + 25 + 16 = x² + 4 + 4x +9

• -14x +41 - 130

• -14x + 28 = 0

• 14x = -28

• = 28/14 X

• x = 2

Answer 2

Answer:

( 3 , 0 )

Step-by-step explanation:

Let that point be ( x , 0 ) , now use formula for distance

$\sqrt{(x - ( - 1)) {}^{2} + (0 - 2) {}^{2} } = \sqrt{(x - 5) {}^{2} + (0 - 4) {}^{2} }$

Square both sides and solve

$\\ {x}^{2} + 2x + 1 + 4 = {x}^{2} - 10x + 25 + 16 \\ \\ 2x + 10x = 25 + 16 - 5 \\ \\ 12x = 36 \\ \\ x = 3$