Question

find the point on x-axis which is equal distance from 2 - 5 and - 2 4​

Answer 1

Answer:

The point is on the x axis. Hence we can assume the coordinate of the point as (h,0).

Now the point is equidistant from (2,-5) and (-2,9).

So (2-h)^{2} + (-5)^{2} = (h+2)^{2} + (-9)^{2}

Simplifying this we get -4h + 29 = 4h + 85

Or 8h = -56 or h= -7

Hence the point is (-7,0) which is equidistant from (2,-5) and (-2,9).