Question

find the point on x axis which is equidistance from points (2,-5) and (-2.9)

Answer 1

x is midpoint of 2 given points (2,-5) and(-2,9)
x(a,b) =
$( \frac{2 + ( - 2)}{2} \frac{( - 5 + 9)}{2} )$
x= (0,2)

point on x axis is 0 ie it lies only on y axis..

Answer 2

(0,2) is the answer....................................