Question

Find the point on X axis which is equidistant from A(_3,4)and B(1,_4)

Answer 1

Hiii friend,

A(-3,4) and B(1,-4) .

Here,

X1 = -3 , Y1 = 4 and X2= 1 , Y2 = -4

Let the required point be P(X,0) .


Then,


PA = PB => PA² = PB²

=> (-3-X)² + (4-0)² = (1-X)² + (-4-0)²

=> (-3)² + (X)² - 2 × (-3) × X + (4)² = (1)² + (X)² - 2 × 1 × X + (-4)²


=> 9 + X² + 6X + 16 = 1 + X² -2X + 16

=> X²-X²+6X+2X = 16-16-9+1

=> 8X = -9+1

=> X = -8/8 => -1


Hence,

The required points is P(X,0) = P(-1,0)



HOPE IT WILL HELP YOU........ :-)