Question

Find the point on X axis which is equidistant from A(_3,4)and B(1,_4)

Answer 1

the coordinates of point which is present on x axis is (x, 0)
let P(x, 0) is equidistant point from A(-3, 4) and B(1, -4)
PA=PB
squaring on both sides
PA^2=PB^2
[x-(-3) ]+(0-4) =(x-1) +[0-(-4) ]
x+3) +16=x^2-2x+1+16
x^2+6x+9+16=x^2-2x+1+16
6x+9=-2x+1
6x+2x=9-1
8x=8
x=8/8
x=1

Answer 2

Answer:

Step-by-step explanation: