Question

Find the point on x-axis which is equidistant from the points (2-2) and (-42)
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Answer 1

Answer:

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P( - 1,0)

Step-by-step explanation:

Let P(x,0) be a point on X-axis .

That means ,

$PA = PB$

$\implies(x - 2)^{2} + (0 + 2)^{2} = (x + 4)^{2} + (0 - 2)^{2}$

$\implies {x}^{2} + 4 - 4x + 4 = {x}^{2} + 16 + 8x + 4$

$= {x}^{2} + 16 + 8x + 4$

$\implies \: - 4x + 4 = 8x + 4$

$\implies \: x = - 1$

$\therefore \: P( - 1,0)$

Hence , we have found the answer .

Answer 2

Answer:

Step-by-step explanation: