Find the point on x axis which is equidistant from the point ( 7,6) and (-3,4)
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Answer:
(X,Y) = (2,5)
Step-by-step explanation:
Mid point has been asked .
Mid point between two co-ordinates is mean of them .
Let the point have co-ordinates = (X,Y)
Then, X= [ 7+(-3) ]/2 & Y = [ 6 + 4]/2
(X,Y) = (2,5)
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