Find the point on x axis which isequidistance from (2,-5) (-2,9)
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Answer: (-7 , 0)
Step-by-step explanation:
let (m,0) be the point as the y co-ordinate of a point on x-axis will be 0 .
distance same means
√[(m-2)²+(0- -5)²] = √[(m+2)²+(0-9)²]
m² - 4m + 4 + 25 = m² + 4m + 4 + 81
8m = 29 - 85 = -56
m = -7
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