find the point on y-axis which is at a distance of root 10 from the point 1, 2, 3
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12
Answer: (0,2,0)
Step-by-step explanation:
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Answered by
20
Answer:
point(0,2,0)
Step-by-step explanation:
Let us assume that the point on y axis is A = (0,y,0) (since, point is on y axis)
And the point given to us be B = (1,2,3)
Given that the distance between the two points is root 10
So,
AB^2 = root 10
(1-0)^2 + (2-y)^2 + (3-0)^2 = 10
1 + (2-y)^2 + 9 = 10
(2-y)^2 = 0
2-y = root 0
-y = -2
y = 2
Hence, the points A is (0,2,0)
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