Question

find the point on y-axis, which is equidistant from (4,1) (-3,5)​

Answer 1

Answer:

Step-by-step explanation:

The distance between (0,y) and (5,−5) is:

(5−0)2+(−5−y)2−−−−−−−−−−−−−−−−√=25+(5+y)2−−−−−−−−−−√

The distance between (0,y) and (1,1) is:

(1−0)2+(1−y)2−−−−−−−−−−−−−−−√=1+(1−y)2−−−−−−−−−−√

The two distances are equal, so also their squares:

25+(5+y)2=1+(1−y)2

Answer 2

Step-by-step explanation:

I hope it will helpful for you